16x^2+239x-15=0

Solution for 16x^2+239x-15=0 equation:

16x^2+239x-15=0

a = 16; b = 239; c = -15;
Δ = b2-4ac
Δ = 2392-4·16·(-15)
Δ = 58081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{58081}=241$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(239)-241}{2*16}=\frac{-480}{32}
=-15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(239)+241}{2*16}=\frac{2}{32}
=1/16
$